File:Catchment-Area-Effective-Vertical-Surfaces.jpeg - Revision history

Joceil.infante at 07:17, 11 April 2017

2017-04-11T07:17:25Z

2017-04-11T07:17:00Z

2017-04-11T07:06:31Z

2017-04-11T07:03:27Z

<math>A= \frac{1}{2} \surd (A_{V,1} + A^2_{V,2} - 2A_{V,1} - A^2_{V,2} \cos \theta)

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<math>A= \frac{1}{2} \surd (A_{V,1} + A^2_{V,2} - 2A_{V,1} - A^2_{V,2} \cos \theta)

← Older revision		Revision as of 07:17, 11 April 2017
Line 1:		Line 1:
	<math>A= \frac{1}{2} \surd (A^2_{v,1} + A^2_{v,2} - 2A_{v,1} - A^2_{v,2} \cos \theta)</math>		<math>A= \frac{1}{2} \surd (A^2_{v,1} + A^2_{v,2} - 2A_{v,1} - A^2_{v,2} \cos \theta)</math>
		+
	Where <math>A_{v,1}</math> and <math>A_{v,2}</math> are areas of the vertical walls, as shown, contributing to the flow of the gutter.		Where <math>A_{v,1}</math> and <math>A_{v,2}</math> are areas of the vertical walls, as shown, contributing to the flow of the gutter.

← Older revision		Revision as of 07:17, 11 April 2017
Line 1:		Line 1:
	<math>A= \frac{1}{2} \surd (A^2_{v,1} + A^2_{v,2} - 2A_{v,1} - A^2_{v,2} \cos \theta)</math>		<math>A= \frac{1}{2} \surd (A^2_{v,1} + A^2_{v,2} - 2A_{v,1} - A^2_{v,2} \cos \theta)</math>
		+	Where <math>A_{v,1}</math> and <math>A_{v,2}</math> are areas of the vertical walls, as shown, contributing to the flow of the gutter.

← Older revision		Revision as of 07:06, 11 April 2017
Line 1:		Line 1:
−	<math>A= \frac{1}{2} \surd (A_{V,1} + A^2_{V,2} - 2A_{V,1} - A^2_{V,2} \cos \theta)	+	<math>A= \frac{1}{2} \surd (A^2_{v,1} + A^2_{v,2} - 2A_{v,1} - A^2_{v,2} \cos \theta)</math>