File:Catchment-Area-Effective-Vertical-Surfaces.jpeg

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Catchment-Area-Effective-Vertical-Surfaces.jpeg ‎(512 × 412 pixels, file size: 80 KB, MIME type: image/jpeg)

$A= \frac{1}{2} \surd (A^2_{v,1} + A^2_{v,2} - 2A_{v,1} - A^2_{v,2} \cos \theta)$

Where $A_{v,1}$ and $A_{v,2}$ are areas of the vertical walls, as shown, contributing to the flow of the gutter.

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	Date/Time	Thumbnail	Dimensions	User	Comment
current	15:03, 11 April 2017		512 × 412 (80 KB)	Joceil.infante (talk \| contribs)	<math>A= \frac{1}{2} \surd (A_{V,1} + A^2_{V,2} - 2A_{V,1} - A^2_{V,2} \cos \theta)

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